From: Kevin Austin (kevin.austin@videotron.ca)
Date: Mon Jan 31 2011 - 22:20:31 EST
... and from the picture, it seems the listener has one ear in the middle of its head.
I knew I had met this somewhere before:
I did a little research on his frequency response, compared to Spock. While Spock had this incredibly wide response, Kryton's was "more often than not".
http://en.wikipedia.org/wiki/Red_Dwarf
Kevin
On 2011, Jan 31, at 2:24 PM, matt ingalls wrote:
> well for stereo at least
> i believe the math for that picture would be:
>
> channel n = cos(45-angle)*source
> channel m = sin(45-angle)*source
>
> where "angle"
> = 0 when the source is panned center.
> = 45 when panned completely to n
> = -45 when panned completely to m
> etc..
>
> ( maybe this is not what you are asking? )
>
>
> and of course any math only really works sitting right in the middle in a dead acoustic
> so if you are making something for a concert environment there might be more practical
> solutions...
>
> -m
>
>
> On Jan 31, 2011, at 4:56 AM, peiman khosravi wrote:
>
>> Thanks. Actually I've read the papers a couple of time. I feel very
>> dumb though as I don't get it! I understand the basic idea that the
>> virtual source position is defined as a vector which then translates
>> to the relative gain of the two speakers (in the case of a 3-D
>> set-up). But I don't understand the actual mathematical formula, I
>> would need a paper written for dummies.
>>
>> And more specifically I would like to know how arrays are represented
>> and dealt with in a programme like max or csound.
>>
>>
>> Best,
>>
>> Peiman
>>
>>
>> On 31 January 2011 03:37, Robert Falesch <calendarius@gmail.com> wrote:
>>> From Ville Pulkki, emerging from his work on the VBAP and RVBAP objects;
>>> formulae in profusion: http://www.acoustics.hut.fi/research/cat/vbap/
>>> Note the first pdf in particular.
>>> --Bob.
>>>
>> <Screen shot 2011-01-31 at 12.53.21.png>
>
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